{"id":230,"date":"2002-09-12T14:12:33","date_gmt":"2002-09-12T14:12:33","guid":{"rendered":"http:\/\/raleighnet.org\/wordpress\/?p=230"},"modified":"2002-09-12T14:12:33","modified_gmt":"2002-09-12T14:12:33","slug":"tell-me-by-any-chance-is-mitch-adopted","status":"publish","type":"post","link":"http:\/\/gator3134.temp.domains\/~raleigh2\/2002\/09\/12\/tell-me-by-any-chance-is-mitch-adopted\/","title":{"rendered":"&#8220;Tell me, by any chance is Mitch adopted?&#8221;"},"content":{"rendered":"<blockquote><p>Why do we divide the total of the squared deviations by <i>n<\/i>-1, rather than <i>n<\/i>? Recall that the sum of the deviations is known to be zero, so given the first <i>n<\/i>-1 deviations, we can always calculate the remaining deviation. This means only <i>n<\/i>-1 of the deviations can vary freely &#8212; the last value is constrained by the values of the preceding deviations. This figure, <i>n<\/i>-1, is known as the <b>degrees of freedom<\/b> and is a value that will become more important in the chapters that follows.<\/p><\/blockquote>\n<p>I&#8217;ve read that paragraph 10 times. I think I finally understand what it&#8217;s saying, but I don&#8217;t think it really answers the question it begins by asking. I need more math training&#8230;..I need A LOT MORE math training.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Why do we divide the total of the squared deviations by n-1, rather than n? Recall that the sum of the deviations is known to be zero, so given the first n-1 deviations, we can always calculate the remaining deviation. This means only n-1 of the deviations can vary freely &#8212; the last value is [&hellip;]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"nf_dc_page":"","om_disable_all_campaigns":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_feature_clip_id":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_post_was_ever_published":false},"categories":[4],"tags":[],"class_list":["post-230","post","type-post","status-publish","format-standard","hentry","category-general"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v28.7 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>&quot;Tell me, by any chance is Mitch adopted?&quot; - gator3134.temp.domains\/~raleigh2<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"http:\/\/gator3134.temp.domains\/~raleigh2\/2002\/09\/12\/tell-me-by-any-chance-is-mitch-adopted\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"&quot;Tell me, by any chance is Mitch adopted?&quot; - gator3134.temp.domains\/~raleigh2\" \/>\n<meta property=\"og:description\" content=\"Why do we divide the total of the squared deviations by n-1, rather than n? 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